14. 1/2 points | Previous Answers SerPSE9 30.P.039.MI.FB My Notes Ask Your Teach

Question

14. 1/2 points | Previous Answers SerPSE9 30.P.039.MI.FB My Notes Ask Your Teacher Four long, parallel conductors carry equal currents of I = 7.60 A. The figure below is an end view of the conductors. The current direction is into the page at points A and B and out of the page at C and D. (a) Calculate the magnitude of the magnetic field at point P, located at the center of the square of edge length -0.200 m. Enter a number allows us to calculate the field of each wire and then add them to find the total field· (b) Determine the direction of the magnetic field at point P, located at the center of the square of edge length f = 0.200 m to the left to the right upward downward into the page out of the page Need Help? Read tMaster Master It Submit Answer Save Progress Practice Another Version

Explanation / Answer

the distance of the point is half the length of diagonal of the square .

d = (1/2)*sqrt(s2 + s2)

d = ( 1/sqrt(2) )*s = 0.2/sqrt2 = 0.141m

magnetic field at point P due to each wire

B = uo*I/2*pi*d = 4*pi*10-7 *7.60/ 2*pi*0.141

B = 10.7*10-6 T

Horizontal component of fields are cancelled and the net field is

Bnet = 4*B*sin45 = 4*10.7*10-6 *sin45

Bnet = 30.26*10-6 T

Bnet = 30.26 uT and directed towards the bottom of the page .

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.