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A block with a mass of 0.378 kg is attached to a spring of spring constant 591 N

ID: 1775590 • Letter: A

Question

A block with a mass of 0.378 kg is attached to a spring of spring constant 591 N/m. It is sitting at equilibrium. You then pull the block down 2.80 cm from equilibrium and let go. What is the amplitude of the oscillation?

A block with a mass of 0.756 kg is attached to a spring of spring constant 591 N/m. It is sitting at equilibrium. You then pull the block down 2.80 cm from equilibrium and let go. What is the amplitude of the oscillation?

A block with a mass of 0.378 kg is attached to a spring of spring constant 1.18×103 N/m. It is sitting at equilibrium. You then pull the block down 2.80 cm from equilibrium and let go. What is the amplitude of the oscillation?

A block with a mass of 0.378 kg is attached to a spring of spring constant 591 N/m. It is sitting at equilibrium. You then pull the block down 5.60 cm from equilibrium and let go. What is the amplitude of the oscillation?

Incorrect. Tries 1/10 Previous Tries

Explanation / Answer

1

The amplitude is the maximum displacement of the oscillation.

The block is pulled with 2.80 cm, it is the maximum displacement, so the amplitude is 2.80 cm

2

The block is pulled with 2.80 cm, it is the maximum displacement, so the amplitude is 2.80 cm

3

The block is pulled with 2.80 cm, it is the maximum displacement, so the amplitude is 2.80 cm

4

The block is pulled with 5.60 cm, it is the maximum displacement, so the amplitude is 5.60 cm

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