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Pad 3:57 AM 30% E a edugen.wileyplus.com WileyPLUS: MyWilcyPLUSI Help Contact Us | Log Out WileyPLUS Cutnell, Physics, 10 GENERAL PHYSICS (PHYS 2001/2002) Home Read, Study & Practice Assignment Gradebook ORION Downloadable eTextbook Assignment > Open Assignment VERSION BACK NEXT ASSIGNMENT RESOURCES Chapter 10, Problem 18 2017 Concept Simulation 10.3 illustrates the concepts pertinent to this problem. A 0.63-kg object is attached to one end of a spring, as in the first drawing, and the system is set into simple harmonic motion. The displacement x of the object as a function of time is shown in the second drawing. With the aid of these data, determine (a) the amplitude A of the motion, (b) the angular frequency w, (c) the spring constant k, (d) the speed of the object at t = 1.0 s, and (e) the magnitude of the object's acceleration at t 1.0 s. Focus on Concepts, blem Problemm Displacamant Time t Pen Problem 27 0m15 the equilibrium position of the objact. hapter 10 Problem blem r (m) Problem 86 0.080 4.0 Objective 0.080 (a) Number (b) Number (c) Number (d) Number (e) Number Units Units Units Units Units LINK TO TEXT Question Attempts: Unlimited SAVE FOR LATER SUBMIT ANSWERExplanation / Answer
Given
mass of the object is m = 0.63 kg ,
from the given graph
a)
the amplitude of the motion is A = 0.080 m
b) the angular frequency is W = 2pi /T
the time period is T = 4 s
so W = 2pi/T = 2pi/4 rad/s = 1.571 rad/s
c) spring constant is k =?
we have relation between W,m,k is W = sqrt(k/m)
k = W^2*m = 1.571^2*0.63 N/m
k = 1.555 N/m
d) from the graph at t = 1.0 s the object is at extream end where the speed become zero so
seed of the object at t=1.0 s is Zero m/s
e) acceleration at t = 1.0 s is
F = KA = ma ==> a = KA/m = 1.555*0.08/0.63 m/s2
a = 0.1975 m/s2
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