Problem 27.42 Part A Treating the stent as a wire loop in the optimum orientatio

Question

Problem 27.42 Part A Treating the stent as a wire loop in the optimum orientation, find the rate of change of magnetic fieild needed for a heating power of 200 mW Express your answer using two significant figures. A stont is a cylindrical tube, often made of metal mesh, thats inserted into a blood vessel to overcome a constriction I sometimes necessary to heat the stent afver insertion to prevent cel growth that couid eause the constriction to recur One method is to place the patient in changing magetc feid, so that induced currents heat the stont. Consider a stainloss-steel stent 12 mm long by 4.5 mm dametor, with total resistance 48 m It's KT/s Submit My Answers Give Up

Explanation / Answer

given,

P= 200 mW = 0.200 W

R= 0.048 ohms

P= I^2R

I= sqrt(P/R ) = sqrt(0.200/0.048) = 2.04 A

r= D/2 = 4.5/2 = 2.25 mm

Area A= pi r^2 = pi*(2.25*10^-3)^2 =1.59 * 10^-5 m^2

E= A(dB/dt)

IR = A(dB/dt)

dB/dt = IR/A = (2.04 *0.048/1.59*10^-5)

dB/dt = 6156.82 = 6.156 KT/s

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