Date: S. A person weighs 750 newtons on the surface of the earth. How far would

Question

Date: S. A person weighs 750 newtons on the surface of the earth. How far would that person need to be from the center of the earth to weigh half as much? Deseribe the circumstanees which contribute to neap tides on earth. (Neap tides are the lowest high tides and the highest low tides.) Consider the angle of sun and moon relative to earth, and the distances of sun and moon from earth. A sketch may help. 10. The equation for centripetal foree is ear with a mass of 1000 kg is going around a curve with a radius of 10 meters. If the maximum centripetal force supplied by friction is 22,500 newtons, what is the fastest speed the car could travel without sliding off the road? 11. Kepler's Third Law states that T2Cr3 for planets in the solar system, where T is the orbital period of a planet, and r is the average distance of that planet from the sun. If T is measured in years, and R is measured in Astronomical Units (AU), then the constant of proportionality, C1 One AU is the average distance of Earth from the sun. Jupiter's average distance from the sun is 5.2 AU. What is the orbital period of Jupiter? AU

Explanation / Answer

here,

8)

weight on earth , W = 750 N

for the weight of object to be half at that on earth

the gravitational accelration at that distance r must be g/2

g/2 = G * me /r^2

9.81 /2 = 6.67 * 10^-11 * 5.98 * 10^24 /( r^2)

solving for r

r = 9.01 * 10^6 m

the height from the center of earth is 9.01 * 10^6 m

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