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A transmission wire oriented parallel to the x-axis carries a current of 200 A f

ID: 1774327 • Letter: A

Question

A transmission wire oriented parallel to the x-axis carries a current of   200 A flowing along the +x direction. A second transmission wire also oriented parallel to the x-axis but lying at a perpendicular distance of   1.15 m below the first wire carries a current of   235 A flowing along the +x direction. What is the magnitude of the total magnetic field at a point midway between the two wires? What is the direction of the net magnetic field?

A transmission wire oriented parallel to the x-axis carries a current of   200 A    flowing along the +x direction. A second transmission wire also oriented parallel to the x-axis but lying at a perpendicular distance of   1.15 m    below the first wire carries a current of   235 A    flowing along the +x direction. What is the magnitude of the total magnetic field at a point   2.3 m directly below a point midway between the two wires? What is the direction of the net magnetic field?

A transmission wire oriented parallel to the x-axis carries a current of   200 A    flowing along the +x direction. A second transmission wire also oriented parallel to the x-axis but lying at a perpendicular distance of   1.15 m    below the first wire carries a current of   235 A     flowing along the +x direction. If the location where the net magnetic field is zero is at perpendicular distance  X from the first wire, what is X ?

A transmission wire oriented parallel to the x-axis carries a current of   200 A    flowing along the +x direction. A second transmission wire also oriented parallel to the x-axis but lying at a perpendicular distance of   1.15 m     below the first wire carries a current of   235 A    flowing along the -x direction. What is the magnitude of the total magnetic field at a point   2.3 m    directly above a point midway between the two wires?

Explanation / Answer


current in first wire I1 = 200 A

current in second wire I2 = 235 A


midpoint is at r = 1.15/2 = 0.575 m


magnetic field due to wire 1 , Bz1 = -uo*I1/(2*pi*r)   in to the page

magnetic field due to wire 2 , B2z = uo*I2/(2*pi*r)   out of the page


net mangnetic field Bnet = B1 + B2

Bnet = (uo/(2*pi*r))*(-I1 + I2)

Bnet = (4*pi*10^-7/(2*pi*0.575))*(-200+235)

Bnet = 1.22*10^-5 T out of page


magnitude 1.22*10^-5 T


direction = +Z direction


=================================

current in first wire I1 = 200 A

current in second wire I2 = 235 A

distance of point from wire 1, r1 = 1.15/2 + 2.3 = 2.875 m

distance of point from wire 2, r2 = 2.3 - 1.15/2 = 1.725 m

magnetic field due to wire 1 , Bz1 = -uo*I1/(2*pi*r1)   in to the page

magnetic field due to wire 2 , B2z = -uo*I2/(2*pi*r2)   in to the page


net mangnetic field Bnet = B1 + B2

Bnet = (uo/(2*pi))*(-I1/r1 - I2/r2)

Bnet = (4*pi*10^-7/(2*pi))*(-200/2.875 - 235/1.725)

Bnet = -4.12*10^-5 T into the page


magnitude = 4.12*10^-5 T


direction = Z direction


===================================================

current in first wire I1 = 200 A

current in second wire I2 = 235 A

distance of point X from wire 1, r1 = x

distance of point X from wire 2, r1 = 1.15 - x


magnetic field due to wire 1 , Bz1 = -uo*I1/(2*pi*r1)   in to the page

magnetic field due to wire 2 , B2z = uo*I2/(2*pi*r2)   out of the page


net mangnetic field Bnet = B1 + B2

Bnet = (uo/(2*pi))*(-I1/r1 + I2/r2)

given Bnet = 0

Bnet = (4*pi*10^-7/(2*pi))*(-200/x + 235/(1.15-x)) = 0


x =0.53 m <<-----ANSWER


=========================================================


current in first wire I1 = 200 A

current in second wire I2 = 235 A

distance of point from wire 1, r1 = 2.3 - 1.15/2 = 1.725 m

distance of point from wire 2, r2 = 1.15/2 + 2.3 = 2.875 m

magnetic field due to wire 1 , Bz1 = uo*I1/(2*pi*r1)   out of the page

magnetic field due to wire 2 , B2z = -uo*I2/(2*pi*r2)   in to the page


net mangnetic field Bnet = B1 + B2

Bnet = (uo/(2*pi))*(-I1/r1 - I2/r2)

Bnet = (4*pi*10^-7/(2*pi))*(200/1.725 - 235/2.875)

Bnet = 6.84*10^-6 T out of the page


magnitude = 6.84*10^-6 T


direction = +Z direction

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