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0/4 (a) If the fish starts from a distance 1.06 m from the base of the ledge ove

ID: 1773462 • Letter: 0

Question

0/4 (a) If the fish starts from a distance 1.06 m from the base of the ledge over which the waterfall flows, find the x and would need to just reach the ledge at the top of its trajectory to jump a waterfall that is 1.30 m high m/s m/s can jump out of the water with a speed of 6.26 m/s) Yes No Need Help? past a does not need to jump to the top of the fal, but only to a point in the fail where the water speed is less than 3,58 m/s; it can then swim up the fall for the remaining salmon must make forward progress in the water, let's assume it can swim to the top if the water speed is 3.00 mvs r speed of 3.58 m/s, but it can jump out of water with a speed of 6.26 m/s. To move that water of the distance only,) (a) If water has a speed of 2.20 m/'s as it passes over a ledge, how far below the ledge will the water be moving with a speed of 3.00 m/s?(t undergoes projectile motion once it leaves the ledge. The water's velocity is intilly horizontal as it passes over the ledge. Enter the (b) tr Type here to search

Explanation / Answer

a) h = 1.30 m

d = 1.06 m

time of flight , t = sqrt(2h/g)

t = sqrt(2 * 1.30/9.8)

t = 0.52 s

vox = d/t = 1.06/0.52

Vox = 2.06 m/s

Voy = g * t = 9.8 * 0.52

Voy = 5.1 m/s

b)
speed = sqrt(5.1^2 + 2.06^2) = 5.5 m/s

Yes , the fish can make the jump