Why friction is only force?mgcos does exert too i think but why not? if t Body r
ID: 1772988 • Letter: W
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Why friction is only force?mgcos does exert too i think but why not? if t Body rolling down an Figure 8.6.1 inclined Body Rolling Down an Inclined Plane As an thustration of laminar motion,westady the motion of a round object c andso on) rolling down an inclined plane. As shown in Figure6 three foces 2 the normal reaction of t on the body. These are (1) the downward force of gravity, (2) the normal plane Fx, and (3) the frictional force parallel to the plane F Choosing the component equations of the translation of the center of mass are5 as (8.63 (8.64 remans where 6 is the inclination of the plane to the horizontal. Because th contact with the plane, we have on -constant (8.65a) Hence, (8.65b) Therefore, from Equation 8.6.4, (866) center of mass is the frictional fore The only force that exerts a momen r The magnitude of this moment is Fpa, where a is the rads of the body rotational equation (Equation 8.6.2) becomes (8.6.7) To discuss the problem further we need to make some assumptions (eo for two etween the plane and the body. We solve the equations of motion for tio casesExplanation / Answer
Mg cos(theta) is the force acting perpendicular to inclined surface. Hence it is equal to normal reaction applied by the surface on object. The direction of this force is through the center of the rolling object. As there is no perpendicular distance between the normal reaction and center of rolling object it cannot produce moment about center.
At point of contact frictional force is tangential to inclined surface and the perpendicular distance from the center of rolling object is its radius hence it only produces a moment of force equal to product of radius and magnitude of force i.e., aFr. Where 'a' radius of rolling body and 'Fr' frictional force.
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