9.A mass of 10.0 Kg is being pulled up a constant inclined plane by a mass of 12
ID: 1772685 • Letter: 9
Question
9.A mass of 10.0 Kg is being pulled up a constant inclined plane by a mass of 12.0 Kg using as string and pulley as shown in the diagram. The angle of the inclined plane to the horizontal is 30°. You may assume that the mass of the string and pulley is insignificant and that there is no friction in the pulley. 10.0 Kg a) If there is no friction, what is the acceleration of the 10.0 Kg 12.0 Kg mass? b) If the coefficient of kinetic friction between the plane and the 10.0 Kg mass is k-0.100, what is the acceleration of the 10 Kg mass? 10, A car takes 10 seconds to go from v-0 to v = 40 m/s at approximately constant acceleration. If wish to find the distance traveled using the equation d = 1 /2 a t2 what value should you use for a?Explanation / Answer
here,
9)
mass 1 , m1 = 10 kg
mass 2 , m2 = 12 kg
theta = 30 degree
a)
the accelration of blocks , a = net force /effective mass
a = ( m2 * g - m1 * g * sin(theta))/(m1 + m2)
a = ( 12 * 9.81 - 10 * 9.81 * sin(30))/( 10 + 12)
a = 3.12 m/s^2
b)
uk = 0.1
the accelration of blocks , a = net force /effective mass
a = ( m2 * g - m1 * g * sin(theta) - uk * m1 * g * cos(theta))/(m1 + m2)
a = ( 12 * 9.81 - 10 * 9.81 * sin(30) - 0.1 * 10 * 9.81 * cos(30))/( 10 + 12)
a = 2.74 m/s^2
10)
v = u + a * t
40 = 0 + a * 10
a = 4 m/s^2
d = 0.5 * a * t^2
d = 0.5 * 4 * 10^2 m = 200 m
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