10 points MI4 16.6.066. A capeo or consists of two charged disks of radius 4 m s
ID: 1772274 • Letter: 1
Question
10 points MI4 16.6.066. A capeo or consists of two charged disks of radius 4 m separated by distance s-2 mm see the figure The magnitude of the charge on each disk is 45 c consider points A B C, and D inside the capacitor, as shown in the diagram. The distance 51 and the distance s2-0.6 mm.(Assume the +x axis is to the right, the ty axis is up, and the +z axis is out.) Notes 1.7 mm, .0 (a) What is the electric fiald inside the capacitor? NIC (b) First, calculate the potential difference WB-YA. What is ' along this path? Whet is Ve VA? volts B VA (c) Next, calculate the potential difference VCB- wat is ' along this path? what is Vc-VB? (d) Finally, calculate the potential difference VA Vc What is i along this path? What is VA VC?Explanation / Answer
a)
r = radius = 4 m
A = area of each disk = pi r2 = (3.14) (4)2 = 50.24 m2
Q = charge = 45 x 10-6 C
d = distance between the plates
V = potential difference between the plates
charge in plate is given as
Q = CV
Q = e A V/d
Q = eA E
45 x 10-6 = (8.85 x 10-12) (50.24) E
E = 1.01 x 105
b)
Vb - Va = E s1 = (1.01 x 105) (1.7 x 10-3) = 171.7 Volts
c)
Vc - Vb = E s2 Costheta
s2 = 0.6 x 10-3 m
Vc - Vb = E s2 Cos90 = 0 Volts
d)
VA - Vc = E s Costheta
s = sqrt(s12 + s22) = sqrt((1.7 x 10-3)2 + (0.6 x 10-3)2) = 1.8 x 10-3 m
Costheta = s1/s = (1.7 x 10-3)/(1.8 x 10-3) = 0.94
VA - Vc = (1.01 x 105 ) (1.8 x 10-3 ) (0.94) = 171 Volts
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