1.00 A ) For the system of capacitors shown in the figure below, find the follow
ID: 1772134 • Letter: 1
Question
1.00 A ) For the system of capacitors shown in the figure below, find the following. (Let C.-5.00 F and C2 C, 6.00 F 2.00 AF C 90.0 V (a) the equivalent capacitance of the system 3.3939 HF (b) the charge on each capacitor 4.28 Your response differs significantly from the correct answer, Rework your solution from the beginnin 120 Your response differs from the correct answer by more than 10%. Double check your calculations. on c on C2 on the 6.00 F capacitor on the 2.00 F capacitor ! (c) the potential difference across each capacitor across C across C2 across the 6.00 F capacitor across the 2.00 F capacitor Need Help? Read it Type here to search
Explanation / Answer
a)
equivalent capacitance = Ceq = 3.3939 uF
b)
C16 = combination of C1 and 6uF = 6 C1/(C1 + 6) = 6 x 5/(6 + 5) = 2.73 uF
V16 = potential difference across the combination of C1 aaand 6 uF = 90 V
Q1 = charge in C1 = Charge in the combination C16 = C16 V16 = 2.73 x 90 = 245.7 uC
Qeq = charge in te equivalent combination = Ceq V = 3.3939 x 90 = 305.5 uC
Q2 = charge in C1 = Qeq - Q1 = 305.5 - 245.7 = 59.8 uC
on 6 uF = Q1 = charge in C1 = = 245.7 uC (since C1 and 6 uF are in series and in series charge remains same)
on 2 uF = Q2 = charge in C2 = = 59.8 uC (since C2 and 6 uF are in series and in series charge remains same)
c)
V1 = potential difference across C1 = Q1/C1 = 245.7/5 = 49.14 Volts
V2 = potential difference across C2 = Q2/C2 = 59.8/1 = 59.8 Volts
V6 = potential difference across 6 uF = 90 - V1 = 90 - 49.14 = 40.86 Volts
V = potential difference across 2 uF = 90 - V = 90 - 59.8 = 30.2 Volts
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