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Question

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Explanation / Answer

Let the resistances be i1, i2, i3, i4 respectively. Applying KVL in three loops,

- 64 - i1 *120 + i4*175 = 0

440 - i2*440 + i4*175 =0

-202 - i3*90 + i4*175 = 0

i1+i2+i3+i4 =0

Solving 4 equation and 4 unknown,

i) current through i1= 0.00673 A

ii) current through 50 ohm i2= 1.147 A

iii) current through 90 ohm i3 = 1.524 A

iv) current through 175 ohm i4= 0.370 A

B) Potential across 175 ohm = 0.370*175 = 64.75 V

  

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