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www.mathxl.com/Student/Play Kimberly Pacheco aspx?homeworkld Math questionld 1&flushed; falseBold 43260938centerw 112: TTh 1-3 Tue 1 Homework: Section 7.3 Homework Score: 0 of 1 pt Kimberly Pacheco 41817 101 AM 4 of 10 (3 complete) v 7.3.38 HW Score: 20%, 2 of 10 pts According to a recent study, some experts believe that 29% of all freshwater fish in a particular country have such high levels of mercury that they are dangerous Suppose a fish market has 250 fish we consider randomly sampled from the population of edible freshwater fish. Use the Central Limit Theorem (and the Empirical Rule) to find the approximate probability that the market wil have a proportion of fish with dangerously high levels of mercury that is more than two standard errors above 0.29. p) is 177.5, and both are more than 10. The approximate probability that the market will have a proportion of fish with dangerously high levels of mercury that is more two standard emons above 029 is than (Round to three decimal places as needed.) Enter your answer in the answer box and then click Check Answer. Clear All All parts showing 3 To see what to study next, go to your Study Plan nu

Explanation / Answer

(a) So as the sample is normal , so probability that the market will have a proportion of fish with dangerousy level of Mercury that is more than twi standard deviation that means Z = +2 , so

Pr ( X> 0.29 + 2 s; 0.29, s) = 1 - 0.9772 = 0.0228

(b) here mean np = 0.04 * 350 = 14

std. dev. = sqrt(np(1-p) = sqrt [ 350 * 0.04 * 0.96] = 3.67

so P( X> = 18) = ?

I am using correction factor here for normal distribution

P( X> = 18) = P(X> 18 - 0.5) = P(X>17.5)

so Z = (17.5 - 14)/ 3.67 = 0.9536

so P(X>17.5) = 1 - 0.8297 = 0.1703

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