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Explanation / Answer

(a)

As given that the ball bounce reverse the y component whereas x component is not change.

so,   1 =   2

angle   2 = 56.1 deg

(b)

lnitial velocity of ball,

vi = vsin1 i + vcos1 j

vi = 3.08*sin(56.1)  + 3.08*cos(56.1)

vi = 2.55i + 1.71j m/s

Final velocity, vf = 3.08*sin(56.1) - 3.08*cos(56.1)

vf =  2.55i - 1.71j m/s

change in velocity of ball,

delta v = vf - vi

delta v = 0 i - 3.43 j

Change in linear momentum,

delta P = m* delta v

delta P = 0.164 * (-3.43)

delta P = 0 i -0.563 j kg.m/s

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