Help please Shadows- OS Mail-massoodsattan@ × Fb Welcome, Massood-BL- · (2) This
ID: 1770757 • Letter: H
Question
Help please
Shadows- OS Mail-massoodsattan@ × Fb Welcome, Massood-BL- · (2) This Life is Mine (f. Statics HW 18 YChegg Study I Guided S/X www.webassign.net/web/Student/Assignment-Responses/submit?dep = 1 7002071 2. 0/20 points | Previous Answers NorEngStatics 1 7.P.047 My Notes Ask Your Teach Determine the areas in mm2 of the surfaces generated by revolving the bent wire ABC (shown) one revolution about the following axes. 270 mm 324 mm 216 mm 810 mm (a) the x-axis 244628.48x mm2 (b) the y-axis 44628.48 3. 15.75/20 points | Previous Answers NorEngStatics17.P.048. My Notes Ask Your Teach Determine the surface areas in in2 and the volumes in in of the bodies of revolution obtained by revolving the bright blue shape one revolution around the following axes. The cutouts on h 4.8 in Type here to search 5:33 PM 11/26/2017Explanation / Answer
a] We know that curved surface area of cone = pi r L and that of frustum = pi(r+R)L
So total area when rotated about x axis
= pi*216*sqrt(216^2+810^2) + pi*(324+216)*sqrt(270^2+540^2)+pi*(540+216)*sqrt(324^2+540^2)
= 3088746 mm^2
b] total area when rotated about y axis
= pi*270*sqrt(270^2+540^2) + pi*810*sqrt(216^2+810^2)+pi*(810+270)*sqrt(324^2+540^2)
= 4782003 mm^2
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.