PHY-133 Section G0 Analytical Physics I Sandy is training to spend time on the I

Question

PHY-133 Section G0 Analytical Physics I Sandy is training to spend time on the Iuternational Space Station by learning to walk ou a 3) a. platform flosting in a pool of oil. The platform has a mass of 110.kg, is 5.00 m long, and floats on the oil without any friction. Sandy, with all her gear on, has a total mass of 65.0 kg. we consider "the system" to consist of Sandy and the platform. 3) b.- a) The platforin is initially tethered 1.00m away from the right eud of the pool. Sandy is . initially at the left end of the platform, and walks with a constaut velocity of 4.00m/s towards the right. What is the kinetic energy of the system when Sandy reaches the right end of the platform? b) The tether is now untied so that the platform loats freely on the oil, starting 1.00m away Now what is the kinetic c) If there's a difference in your answers between Parts a and b, explain why that is so. Where d) When Sandy reaches the right eud of the platform in Part b, how far away is the platform e) Sandy is now given a 10.0kg lead weight to throw. On land, she can throw it 4.50 m. She from the right end of the pool. Sandy again starts at the left end of the platform and walks right with a constant velocity of 4.00 m/s relative to the platform. energy of the system when Sandy reaches the right ead of the platform? did the energy go? from the right end of the pool? again stands at the left end of the untethered platform, which is again initially 1.00m away from the right end of the pool. She now throws the weight to the right. Exactly where does it land relative to the right end of the platform? Where does it land relative to the right end of the pool? f) 5.00 m 1.00 m 65.0 kg 110 Figure 3 - Sandy the astronaut trains by walking on a platform Bloeting frictionlesly on a pool of oil. Pleose onsue 5and

Explanation / Answer

as the effect of frictional forces are zero,it implies she is moving with uniform velocity now the relative distance is 4m , ie 5m - 1 m = 4m . so the distance at which it falls is 4m

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