2)What is F bc,x , the x-component of the force exerted by the infinite wire on

Question

2)What is Fbc,x, the x-component of the force exerted by the infinite wire on segment bc of the loop?

3)What is Fnet,y, the y-component of the net force exerted by the infinite wire on the loop?

4)Another infinite straight wire, aligned with the y-axis is now added at a distance 2L = 72 cm from segment bc of the loop as shown. A current, I3, flows in this wire. The loop now experiences a net force of zero.

What is the magnitude of I3?

A rectangular loop of wire with sides H = 25 cm and w = 54 cm carries current 12 = 0.256 A. An infinite straight wire, located a distance L 36 cm from segment ad of the loop as shown, carries current 11 = 0.672 A in the positive y-direction. a W I 1) What is Fad,x, the x-component of the force exerted by the infinite wire on segment ad of the loop?

Explanation / Answer

1

Fad,x = uoi1i2H/(2piL) = (4pi*10-7)(0.672)(0.256)((0.25)/2pi*0.36

Fad,x=2.39*10-8 N

2

Fbc,x =uoi1i2H/2pi(L+W) = (4pi*10-7)(0.672)(0.256)((0.25)/2pi*(0.36+0.54)

Fbc,x=9.56*10-9 N

3

Fnet,y = 0

since force acting on perpendicular wire is zero.

4

Fad,x'= uoi3i2H/2pi(2L) = [(4pi*10-7)(0.256)((0.25)/4pi*0.36]I3=1.78*10-8I3

Fbc,x' =uoi1i3H/2pi(2L+W) = [(4pi*10-7)(0.672)(0.25)/2pi*(2*0.36+0.54)]*I3=2.67*10-8I3

Net force acting on the loop is zero

Fad,x+Fbc,x =Fad,x' +Fbc,x'

2.39*10-8+9.56*10-9=(1.78*10-8+2.67*10-8)*I3

I3=0.7528 A

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