A m 1 = 13.0 kg object and a m 2 = 11.0 kg object are suspended, joined by a cor

Question

A m1 = 13.0 kg object and a m2 = 11.0 kg object are suspended, joined by a cord that passes over a pulley with a radius of 10.0 cm and a mass of 3.00 kg (Fig. P10.46). The cord has a negligible mass and does not slip on the pulley. The pulley rotates on its axis without friction. The objects start from rest 3.00 m apart. Treating the pulley as a uniform disk,determine the speeds of the two objects as they pass each other. (Hint: There are two ways to do this problem: (1) The easy method is with conservation of energy; (2) The hard method is with torque and angular acceleration. If you choose this more challenging method, note that the tensions on either side of the pulley are NOT the same.)

Explanation / Answer

here,

m1 = 13 kg , m2 = 11 kg

mass of pulley , M = 3 kg

radius , r = 0.1 m

the accelration of the system , a = net force /effective mass

a = ( m1 - m2) * g /( m1 + m2 + I/r^2)

a = ( 13 - 11) * 9.81 /( 13 + 11 + 0.5 * 3)

a= 0.77 m/s^2

for the two blocks to pass each other , they have travel , h = 3/2 = 1.5 m

the final speed of blocks , v = sqrt(2*a*h)

v = sqrt(2*0.77 * 1.5) = 1.52 m/s

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.