A m 1 = 1.75-kg aluminum block and a m 2 = 6.05-kg copper block are connected by
ID: 1323313 • Letter: A
Question
A m1 = 1.75-kg aluminum block and a m2 = 6.05-kg copper block are connected by a light string over a frictionless pulley. The two blocks are allowed to move on a fixed steel block wedge (of angle
? = 32.0?)
as shown in the figure. Making use of this table, determine the following.
(a) the acceleration of the two blocks
_____________ m/s2
(b) the tension in the string
_____________ N
Explanation / Answer
Regarding that acceleration of gravity is 9.8 m/s2
According to the diagram of free body W=weight of M2 and F= the strength parallel to the slope
Then F= M2*g*sen(32)=31.419 N
According to the second law of Newton, we have the following equation
F-T=M2*a (1)
And
T=M1*a (2)
Replacing eq. (2) in (1) , we can obtain the value of a=4.03m/s2
Furthermore using the equation (2) , we have the value of T=7.05N
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