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A 55.0 kg ballet dancer stands on her toes during a performance with four square

ID: 1770479 • Letter: A

Question

A 55.0 kg ballet dancer stands on her toes during a performance with four square inches (26.0 cm2) in contact with the floor. What is the pressure exerted by the floor over the area of contact in the following cases? (a) if the dancer is stationary 206250 (b) if the dancer is leaping upwards with an acceleration of 5.00 m/s2 283333 33X Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. Pa Pa

Explanation / Answer

(A) Fnet = F - m g = 0

F = m g = 55 x 9.8 = 539 N  

P = F / A = (539) / (26 x 10^-4 m^2)

P = 207308 Pa ....Ans

(B) Fnet = F - m g = m a

F = 55 ( 9.8 + 5) =814 N  


P = F / A = (814) / (26 x 10^-4)

P = 313077 Pa

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