2. The location of Auburn is Lat 32.6° N Long 85.5° W. At solar noon on 21 March

Question

2. The location of Auburn is Lat 32.6° N Long 85.5° W. At solar noon on 21 March (the spring equinox) the maximum (cloudless) irradiance on a fixed tilt angle solar panel tilted at 32.6 towards the southern sky on the E-W axis is.... 6 SIs 18 IR=0 IR = 0 18 t 24 t=ToD.hr Assuming the earth's orbit is circular, compute the daily insolation on a..21 March (vernal equinox) b..21 June (summer solstice: day length 14.15 hr) c..21 Sept (autumnal equinox) d..21 Dec (winter solstice: day length 9.85 hr)

Explanation / Answer

Irradiance and insolation are terms used interchangeably

a. On 21st March when day length(t) is 12 hours insolation is 1kW/squaremeter

b. On 21st June when day length is 14.15 hours insolation is Cos(2.15/12pi or32.5degrees)  

    kW/squaremeter = 0.843391446kW/squaremeter

c. on 21st September again daylength is 12 hours and insolation is again 1kW/squaremeter

d. on 21st December the daylength is 9.85 hours and insolation is again Cos(32.5 degrees)=

   0.843391446kW/squaremeter

Related Questions

Navigate

• Browse (All)
• Browse 2
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.