Test 2 Physics 27005 Answer 6 out of the 7 questions. Hand in all work. 1.. A 25

Question

Test 2 Physics 27005 Answer 6 out of the 7 questions. Hand in all work. 1.. A 250-kg crate is placed on an adjustable inclined plane. If the crate slides down the incline with an acceleration of 0.70 m/s^2 when the incline angle is 25 degree, then what should the incline angle be for the crate to slide down the plane at constant speed? (g = 9.8 m/s^2) 2. A 150-N sled is pulled up a 28 degree slope at a constant speed by a force of 100 N. What is the coefficient of kinetic friction between sled and slope? 3. A simple pendulum, 2.0 m in length, is released with a push when the support string is at an angle of 25 degree from the vertical. If the initial speed of the suspended mass is 1.2 m/s when at the release point, what is its speed at the bottom of the swing? (g = 9.8 m/s^2) 4.Hooke's law spring is compressed 6.0 cm from equilibrium, and the potential energy stored is 18.0 J. What compression (as measured from equilibrium) would result in 100 J being stored in this case? 5.A boy throws a 0.15-kg rubber ball down onto the floor. The ball?s speed just before impact is 6.5 m/s, and just after is 3.5 m/s. If the ball is in contact with the floor for 0.025 s, what is the magnitude of the average force applied by the floor on the ball? 6. An Astronaut weighs 60 kg. She is space walking outside the space shuttle and pushes a 350-kg satellite away from the shuttle at 0.90 m/s. which also stops her motion. What speed does this give her as she moves toward the shuttle? 7. 0.40-kg mass, attached to the end of a 0.75-m string, is whirled around in a circular horizontal path. 1f the maximum tension that the string can withstand is 450 N, then what maximum speed can the mass have if the string is not to break?

Explanation / Answer

let spring constant be k and x be displacement of the sping from equilibrium position.

potential energy = 1/2 * k * x2

therefore, 1/2 * k * x2 = 18 J

converting 6 cm to metres.

k = 106 N/m

now for 100 J applying the same equation

1/2 * k * x2 = 100 J

substituting value we get x=14.14 cm (approximately).

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