A guitar string with mass density u=.0023kg/m is L=0.96m long on the guitar. The

Question

A guitar string with mass density u=.0023kg/m is L=0.96m long on the guitar. The string is tuned by adjusting the tension to T=92.3 N
1)with what speed do the waves on the string travel?
2)what is the fundamental frequency for this string?
3)someone places a finger a distance 0.152 m from the top end of the guitar. What s the una mental frequency in this case?
4)to "down tune" the guitar (so everything plays at a lose frequency) how should the tension be adjusted? -increase the tension -decrease the tension -changing he tension will only alter the velocity not the frequency A guitar string with mass density u=.0023kg/m is L=0.96m long on the guitar. The string is tuned by adjusting the tension to T=92.3 N
1)with what speed do the waves on the string travel?
2)what is the fundamental frequency for this string?
3)someone places a finger a distance 0.152 m from the top end of the guitar. What s the una mental frequency in this case?
4)to "down tune" the guitar (so everything plays at a lose frequency) how should the tension be adjusted? -increase the tension -decrease the tension -changing he tension will only alter the velocity not the frequency
1)with what speed do the waves on the string travel?
2)what is the fundamental frequency for this string?
3)someone places a finger a distance 0.152 m from the top end of the guitar. What s the una mental frequency in this case?
4)to "down tune" the guitar (so everything plays at a lose frequency) how should the tension be adjusted? -increase the tension -decrease the tension -changing he tension will only alter the velocity not the frequency

Explanation / Answer

1)
v=(T/?)^1/2
v=(92.3/2.3x10^-4)^1/2 = 401.3m/s

2)
v=Lf
f=v/L
f=401.3/0.96=418.02 Hz

3)
f=v/(L-0.152)
f=401.3/(0.96-0.152)=496.65 Hz

4)
f=v/L
f=(1/L)(T/?)^1/2
to down tune must decrease T

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