osm mod o e Mayville State Universty P- x saplingle ming com C chegg com Questio
ID: 1769432 • Letter: O
Question
osm mod o e Mayville State Universty P- x saplingle ming com C chegg com Question 11 of 12 A liquid of density 1.35 x 10 kg/m3 flows and At location 1 along the pipe the speed is and the 11.5 cm is 11.5 cm. At location 2 the pipe diameter is 17.7 cm. At location 1 the pipe is 9.33 m higher than it is at location 2. Ignoring calculate the difference between the fluid pressure at location 2 and the fluid pressure at location 1. 9.33 m 17.7 O Previous ® Give Up 8 View solution check Answer 0 Next about us careers partners privacy policy terms of useExplanation / Answer
A1 = p1*r1^2
A2 = pi*r2^2
from equation of continuity
A1*v1 = A2*v2
v2 = A1*v1/A2
v2 = (11.5/17.7)^2*9.25 = 3.904 cm /s
bernoullis pricilple
P1 + 0.5*rho*v1^2 + rho*g*h = P2 + 0.5*rho*v2^2
P2 - P1 = 0.5*rho*(v1^2 - v2^2) + rho*g*h
P2-P1 = (0.5*1350*((0.0925*0.0925)-(0.03904*0.03904))) + (1350*9.8*9.33)
P2 - P1 = 123440.65 Pa <------------answer
P2 - P1 = 123.44065 Kpa
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