A mountain climber friend with a massive 78 kg ponders the idea of attaching a h

Question

A mountain climber friend with a massive 78 kg ponders the idea of attaching a helium filled balloon perfect only reduce his way by 25% when he climbs he wonders what the approximate size of such a bullet would be hearing of your physics skills he asks you share with him your calculations that find the volume of the balloon A mountain climber friend with a massive 78 kg ponders the idea of attaching a helium filled balloon perfect only reduce his way by 25% when he climbs he wonders what the approximate size of such a bullet would be hearing of your physics skills he asks you share with him your calculations that find the volume of the balloon

Explanation / Answer

To effectively lift (0.25)(78 kg) = 19.5 kg the mass of displaced air would be 19.5 kg.
Density of air is about 1.2 kg/m3. From density = mass/volume, the volume of 19.5 kg of
air, also the volume of the balloon (neglecting the weight of the hydrogen) would be
vol = mass/density = (19.5 kg)/(1.2 kg/m3) = 16.25 m3, slightly more than 3 m in diameter
for a spherical balloon.

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