A turtle ambles leisurely-as the turtles tend to do-when it moves from a locatio

Question

A turtle ambles leisurely-as the turtles tend to do-when it moves from a location with position vector r1x= 1.29m and r1y= -2.69m in a lettuce garden to another location, with position vector r2x= 3.33m and r2y= -4.37m, where the lettuce appears to be tastier (but really isn't -this turtle can't see too well). The excursion takes 308 seconds to complete. What are the components and the magnitude of the turtle's average velocity, in meters per second?
Vavx=______________m/s V avy=______________m/s |Vav|=______________m/s

Can someone please explain how to get all three answers I've seen examples and I'm still lost. A turtle ambles leisurely-as the turtles tend to do-when it moves from a location with position vector r1x= 1.29m and r1y= -2.69m in a lettuce garden to another location, with position vector r2x= 3.33m and r2y= -4.37m, where the lettuce appears to be tastier (but really isn't -this turtle can't see too well). The excursion takes 308 seconds to complete. What are the components and the magnitude of the turtle's average velocity, in meters per second?
Vavx=______________m/s V avy=______________m/s |Vav|=______________m/s

Can someone please explain how to get all three answers I've seen examples and I'm still lost.
Vavx=______________m/s V avy=______________m/s |Vav|=______________m/s

Can someone please explain how to get all three answers I've seen examples and I'm still lost.

Explanation / Answer

VAvx = (r2x-r1x)/t = (3.33-1.29)/308 = 6.62*10^-3 m/s

VAvy = (r2y-r1y)/t = (-4.37-(-2.69) )/308 = -5.45*10^-3 m/s

|Vav| = sqrt(VAvx^2+Vavy^2)

= 8.57*10^-3 m/s

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