A 2lbm mass is placed on a piston of diameter 6 inches. (Assume mass is combined
ID: 1767729 • Letter: A
Question
A 2lbm mass is placed on a piston of diameter 6 inches. (Assume mass is combined mass of block and piston.) Gage A reads 2psi.
a.) Calculate the pressure reading on Gage B.
b.) Calculate h. (Dont forget about atmospheric pressure acting on top of the piston.)
Thank you!
A 2lbm mass is placed on a piston of diameter 6 inches. (Assume mass is combined mass of block and piston.) Gage A reads 2psi. Calculate the pressure reading on Gage B. Calculate h. (Dont forget about atmospheric pressure acting on top of the piston.)Explanation / Answer
Gage A and B measure gage pressures.
Pressure in right tank = 2 psi gage
Absolute pressure in right tank = 14.7 + 2 = 16.7 psia
Reading of gage B = 107.2 - 16.7 = 90.5 psi (gage)
B)
Area of piston = 3.14 / 4 *6^2 = 28.26 in^2
Pressure due to mass = Force / area = 2 / 28.26 = 0.0708 psi
Atmospheric pressure = 14.7 psi
Total abs pressure in left tank = 14.7 + 0.0708 = 14.7708 psia
We have, 14.7708 = rho*h + 16.7
Using rho = 62.4 lb / ft^3 = 62.4 / 12^3 lb/in^3 for water we get
14.7708 = (62.4/12^3)*h + 16.7
h = -53.42 in
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