please help!!! A person shoots a tennis ball out of a launcher. The tennis ball

Question

please help!!!

A person shoots a tennis ball out of a launcher. The tennis ball rises to a maximum height of 38

meters.

a. What is the initial velocity of the tennis ball out of the launcher?

b. How long (in seconds) is the tennis ball in the air before it hits the 38 meter mark?

c. Graph y as a function of t. What is the equation of this graph? What is the first

derivative of this equation?

d. Graph v as a function of t. What is the equation of this graph? What is the first

derivative of this equation?

e. Graph a as a function of t. What is the equation of this graph?

Explanation / Answer

Assuming vertical motion

a) V^2 = 2*g*h

v = sqrt(2*9.8*38) = 27.29 m/s

b) t = v/g = 27.29/9.8 = 2.785 s

c) y = 27.29*t - 4.9*t^2

d) v = 27.29 - 9.8*t

e) a= -9.8 m/s^2 i.e. constant

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