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TALLE B1. MIXING WATER AND AIR CONTENT Mixing Water tbJewyd Mortar/8 in.1/2 in..

ID: 1765656 • Letter: T

Question

TALLE B1. MIXING WATER AND AIR CONTENT Mixing Water tbJewyd Mortar/8 in.1/2 in..1 %în. Non-Air Entrained Cencrets 315 360 Air-Estraised Concrete 305 420 85 65 240 350 300 28 385 3-4 6-7 Exposur Moderate7.5 380 325 295 275 265 225 Recommended Air Content, % 4.0 6.0 7.5 5.5 7.0 5.0 6.5 5.0 6.5 3.5 5.0 9.0 6.0 Moderate Exposare Where freezing temperatures are expected, but the coscrete will not be saturated for extended periods prior to freezing, and will not be exposed to deicing salts Examples: Exterior beams; columns; walis; abutments; exterior slabs under soofs Severe Exposure Where concrete will be exposed to deicing salts, or where concrete will be in contact with water and will potentially be saturated prior to freezing Eamples Pavements bridge decks curbes suters siderwalks, comal and pond linings terlks TABLE 82. COARSE AGGREGATE CONTENT b/b, for different Fineness Modulus of Fine 2.20 2.40 2.60 2.80 3.00 0.68 0.66 0.64 0.62 0.60 Nominal Maximum Size Coarse2 38 n. 0.52 0.500.48 0.46 0.4 1/2 in. 0.61 0.59 0.57055 0.53 3/4 in. in. 0.73 0.71 0.69 0.67 0.65 1% in. | 0.77 0.75 0.73 0.71 0.69 2 in. 0.80 0.78 0.76 0.74 0.72 0.76 0.80 0.78 0.84 in b/b, is the volume of dry-rodded coarse aggregate in a unit volume of concrete

Explanation / Answer

Given data:

Total cementitous material=752 lbs

Cement=601.6 lbs

Fly ash=150.4 lbs

Calculation of water content:

For a nom-MSA of 1.5" and slump of 3"

Water content=295 lbs

Given that reduction of 1/2 gallon per cubic yard of reduction and 5% of reduction due to Type A water reducer

Water content=295 lbs/yard3-13.75 lbs-0.5x8.35x lbs/yard3

Water content=277 lbs

Water /Cement=277/752=0.36

Mixing water=277 lbs

Air content=6%

Cement=601.6 lbs

Fly ash=150.4 lbs

Total cementitous sacks=2.06 sacks (752 lbs=2.06 sacks)

For rocks:

b/b0=2.9

druw (dry rodded unit weight)=101 pcf

Rock (lbs)=101x27x0.70=1908.9 lb/yard3

Using the absolute volume method calculate the quantities of the materials:

Cement=601.6/(3.15x62.4)=3.06 cu.ft

Water=277/62.4=4.43 cu.ft

Air=6/100x27=1.62 cu.ft

Rocks=1908.9/(2.67x62.4)=11.45 cu.ft

The calcualted quantities of all materials except sand=3.06+4.11+1.62+11.45=20.24 cu.ft

Quantity of sand=27-20.24=6.76 cu.ft

Weight of sand=6.76x62.4x2.65=1117.8 lbs

1 cubic yard batch weights

Cement=601 lbs

Fly ash=150 lbs

Water=277 lbs

Rock=1908.9 lbs

Sand=1117.8 lbs

Water reducer=3.5x601.6/100=21.056 fl-oz

If any corrections are required they may be corrected in the site by moisture content, as the data is not given here we can assume the above steps may be used as the final data