TABLE II (cont.) Areas under the standard normal curve Second decimal place in z
ID: 2947366 • Letter: T
Question
TABLE II (cont.) Areas under the standard normal curve Second decimal place in z 0.00 0.02 0 004 005 0.0007 0.08 0.09 0.0 0.5000 0.5040 0.5080 0.5120 0.5160 0.5199 0.5239 0.5279 0.5319 0.5359 . 0.5398 0.5438 0.5478 0.5517 0.5557 0.5596 o.5636 0.5675 0.5714 0.5753 02 0.5793 0.5832 0.5871 0.5910 0.5948 0.5987 0.6026 0.6064 0.6103 0.6141 03 0.6179 0.6217 0.6255 0.6293 0.6331 0.6368 0.6406 0.6443 0.6480 0.6517 04 0.6554 0.6591 0.6628 0.6664 0.6700 0.6736 0.6772 0.6808 0.6844 0.6879 0 05 0.6915 0.6950 0.6985 0.7019 0.7054 0.7088 0.7123 0.7157 0.7190 0.7224 0.6 0.7257 0.7291 0.7324 0.7357 0.7389 0.7422 0.7454 0.7486 0.7517 0.7549 0.7 0.7580 0.7611 0.7642 0.7673 0.7704 0.7734 0.7764 0.7794 0.7823 0.7852 0.8 0.7881 0.7910 0.7939 0.7967 0.7995 0.8023 0.8051 0.8078 0.8106 0.8133 09 0.8159 0.8186 0.8212 0.8238 0.8264 0.8289 0.8315 0.8340 0.8365 0.8389 10 0.8413 0.8438 0.8461 0.8485 0.8508 0.8531 0.8554 0.8577 0.8599 0.8621 11 0.8643 0.8665 0.8686 0.8708 0.8729 0.8749 0.8770 0.8790 0.8810 0.8830 2 0.8849 0.8869 0.8888 0.8907 0.8925 0.8944 0.8962 0.8980 0.8997 0.9015 13 0.9032 0.9049 0.9066 0.9082 0.9099 0.9115 0.9131 09147 0.9162 0.9177 14 0.9192 0.9207 0.9222 0.9236 0.9251 09265 0.9279 0.9292 0.9306 0.9319 15 0.9332 0.9345 0.9357 0.9370 09382 09394 0.9406 09418 09429 0.9441 16 0.9452 0.9463 0.9474 0.9484 0.9495 0.9505 0.9515 0.9525 0.9535 0.9545 1.7 0.9554 0.9564 0.9573 0.9582 0.9591 0.9599 0.9608 0.9616 0.9625 0.9633 18 0.9641 0.9649 0.9656 0.9664 0.9671 0.9678 0.9686 0.9693 09699 0.9706 Using Table II, a) The z-score that has an area of 0.7422 to its left is z- b) The z-score that has an area of 0.7055 to its left is z c) The z-score that has an area of°.9500 to its left zExplanation / Answer
Solution :
From given table,
1)
P(Z < z) = 0.7422
P(Z < 0.65) = 0.7422
z = 0.065
2)
P(Z < z) = 0.7055
P(Z < 0.54) = 0.7055
z = 0.54
3)
P(Z < z) = 0.9500
P(Z < 1.645) = 0.9500
z = 1.645
4) P(Z < -2.47) = 0.0068
Area = 0.0068
5) P(Z > -2.47) = 1 - P(Z < -2.47) = 1 - 0.0068 = 0.9932
Area = 0.9932
6) P(Z > 2.47) = 1 - P(Z < 2.47) = 1 - 0.9932 = 0.0068
Area = 0.0068
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