Your friend has a pair of fuzzy dice with a mass of 1.31 g hanging from his rear

Question

Your friend has a pair of fuzzy dice with a mass of 1.31 g hanging from his rear-view mirror. (a) When he accelerates from a stoplight, thedice deflect backward toward the rear of the car hanging at anangle of 6.10° relative to thevertical. Find the tension in the string holding the dice.
N

(b) At what angle to the vertical will the tension in the string betwice the weight of the dice?
°
(a) When he accelerates from a stoplight, thedice deflect backward toward the rear of the car hanging at anangle of 6.10° relative to thevertical. Find the tension in the string holding the dice.
N

(b) At what angle to the vertical will the tension in the string betwice the weight of the dice?
°

Explanation / Answer

From the forces acting on the dice: . horizontal:     T sin6.10 = ma . vertical:          T cos6.10 = mg . Using second equation: .           T = mg / cos6.10 = 0.00131 * 9.80 /cos6.10 =  0.0129 newtons . Now, use the same idea but the angle is unknownand   T is 2mg .      2mg cos = mg .     cos = 1/2            = 60 degrees

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