King Arthur\'s knights fire a cannon from the top of the castlewall. The cannonb

Question

King Arthur's knights fire a cannon from the top of the castlewall. The cannonball is fired at a speed of 55 m/s and an angle of29 degrees above the horizontal. A cannonball that wasaccidentally dropped hits the moat below in 1.6 s. A. How far from the castle wall does the cannonball hitthe ground? B. What is the ball's maximum height above theground? King Arthur's knights fire a cannon from the top of the castlewall. The cannonball is fired at a speed of 55 m/s and an angle of29 degrees above the horizontal. A cannonball that wasaccidentally dropped hits the moat below in 1.6 s. A. How far from the castle wall does the cannonball hitthe ground? B. What is the ball's maximum height above theground?

Explanation / Answer

The world at that time knew nothing of gun powder. But.. a) The horizontal component  Vh is Vh= Vcos(29) = 55 x cos(29)= 48.1m/s and since t= 1.6 s The ball has also traveled up and down with initial velocityVv= Vsin(29) =26.7 m/s t= 2(Vv/g) = 2(26.7/9.8) t= 5.4 s S=Vh t = 48.1 x (1.6 + 5.4 ) =339m b) h= 0.5gt2   h= 0.5x9.8x (1.6)2 h= 12.5m this is height above the point of fire h= 12.5m the ball climed at initial velocity Vv = Vsin(29) = 26.7 m/s t'=Vv /g and then h'= 0.5g(t')2   h'= 0.5g(Vv /g)2   h'= 0.5(Vv )2/g h'= 0.5(26.7)2/9.8 = 36.3m finally H=h + h' = 12.5 + 35.3 = 47.8m

Related Questions

Navigate

• Browse (All)
• Browse K
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.