A heavy box (100.0 kg) is sittingstill on a warehouse floor, despite the efforts

Question

A heavy box (100.0 kg) is sittingstill on a warehouse floor, despite the efforts of a worker to pushit (with a force of 350.0 N). Ifthe coefficient of static friction between the box and the floor is0.6, what is the friction force between the box and the floor? Whatis the frictional force between the box and the floor if anotherworker puts another box (also 100.0 kg) on top of the first box while the firstworker continues to pull with 350.0 N? f (one box) =
N f (two boxes) = N

f (one box) =
N f (two boxes) = N

f (one box) =
N f (two boxes) = N

Explanation / Answer

The frictional force fs = mg = 0.6 * 100 * 9.8 =588 N The frictional force when 100 kg box put on first boxfs = (m1+m2)g = 0.6*200*9.8 = 1176 N

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.