(a) With these choices, find the ball\'s maximumheight above the ground, and the

Question

(a) With these choices, find the ball's maximumheight above the ground, and the time it takes to reach the maximumheight.
Maximum height above ground Enter anumber. m Time to reach maximum height Enter anumber. s
(b) Repeat your calculations choosing the origin at the base of thebuilding. Maximum height above ground Enter anumber. m Time to reach maximum height Enter anumber. s Enter anumber. Enter anumber. Enter anumber. Enter anumber. Maximum height above ground Enter anumber. m Time to reach maximum height Enter anumber. s

Explanation / Answer

height of the building H = 57.0 m
the initial horizontal velocity U = 9.50 m/s the initial vertical velocity u = 11.0 m/s (a). the ball's maximum height above the ground is H ' =h Since origin is at the top of the building where h = height reached by ball above the top of thebuilding              = u ^ 2 / 2g              = 6.173 m Let the time it takes to reach the maximum height be tthen    t = u / g      = 11/ 9.8 = 1.122 s (b). the ball's maximum height above the ground is H ' =H + h Since origin is at the top of the building where h = height reached by ball above the top of thebuilding              = u ^ 2 / 2g              = 6.173 m So, H ' = 63.17 m Let the time it takes to reach the maximum height be tthen    t = u / g      = 11/ 9.8 Since origin is at the top of the building where h = height reached by ball above the top of thebuilding              = u ^ 2 / 2g              = 6.173 m So, H ' = 63.17 m Let the time it takes to reach the maximum height be tthen    t = u / g      = 11/ 9.8       = 1.122 s

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