(a) When a projectile is launched horizontally from a rooftopat a speed of v 0 x
ID: 1737045 • Letter: #
Question
(a) When a projectile is launched horizontally from a rooftopat a speed of v0x, does its horizontalcomponent ever change in the absence of air resistance? (yes orno)(b) Can you calculate the horizontal distance D traveledafter launch simply as D =v0xt, where t is thefall time of the projectile?
(Yes or No)
(c) In calculating the fall time, is the vertical part of themotion just like that of a ball dropped from rest?
(yes or no)
Explain each of your answers.
A criminal is escaping across a rooftop and runs off the roofhorizontally at a speed of 4.5 m/s, hopingto land on the roof of an adjacent building. The horizontaldistance between the two buildings is D, and the roof ofthe adjacent building is 2.0 m below thejumping off point. Find the maximum value for D.
m (a) When a projectile is launched horizontally from a rooftopat a speed of v0x, does its horizontalcomponent ever change in the absence of air resistance? (yes orno)
(b) Can you calculate the horizontal distance D traveledafter launch simply as D =v0xt, where t is thefall time of the projectile?
(Yes or No)
(c) In calculating the fall time, is the vertical part of themotion just like that of a ball dropped from rest?
(yes or no)
Explain each of your answers.
A criminal is escaping across a rooftop and runs off the roofhorizontally at a speed of 4.5 m/s, hopingto land on the roof of an adjacent building. The horizontaldistance between the two buildings is D, and the roof ofthe adjacent building is 2.0 m below thejumping off point. Find the maximum value for D.
m
Explanation / Answer
a) no, because no acceleration in horizontal direction. b) yes, in horizontal direction, it is a constant velocitymotion, c) yes, because initial velocity in vertical direction is zero. vertical displacement h = 2.0 m, initial velocity v = 4.5 m/s time = t h = gt2/2, so t = (2h/g) the distance D = vt = v(2h/g) = 2.87 m
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