Figure 4-61 shows the path taken by a drunk skunk over levelground, from initial
ID: 1762753 • Letter: F
Question
Figure 4-61 shows the path taken by a drunk skunk over levelground, from initial point i to final point f.The angles are 1 = 33.0°, 2 =52.0°, and 3 = 76.0°, and the distancesare d1 = 4.80 m, d2 = 7.20m, and d3 = 13.0 m. What are the(a) magnitude and (b) angle ofthe skunk's displacement from i to f? Give theangle as a positive (counterclockwise) or negative (clockwise)angle of magnitude less than 180°, measured from the+x direction. Figure 4-61 shows the path taken by a drunk skunk over levelground, from initial point i to final point f.The angles are 1 = 33.0°, 2 =52.0°, and 3 = 76.0°, and the distancesare d1 = 4.80 m, d2 = 7.20m, and d3 = 13.0 m. What are the(a) magnitude and (b) angle ofthe skunk's displacement from i to f? Give theangle as a positive (counterclockwise) or negative (clockwise)angle of magnitude less than 180°, measured from the+x direction.Explanation / Answer
from the given figure the threedisplacements can be written as d1 =d1 (cos1 i^ + sin1j^) d2 =d2 [cos(180o + 1 -2) i^ + sin (180o + 1- 2) j^] d3 =d3 [cos(360o - 3 -2 + 1) i^ + sin(360o - 3 -2 + 1) j^] the net displacement will be d= d1 +d2 +d3 the direction will be = tan-1(dy /dx) = ........oRelated Questions
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