A baseball leaves the bat with a speed of 44m/s and an angleof 30 degrees above

Question

A baseball leaves the bat with a speed of 44m/s and an angleof 30 degrees above the horizontal. A 5.0m fence is locatedat a horizontal distance of 132m from the point where the ball isstruck. Assume the ball leaves the bat 1m above the groundlevel. a) How long is the ball in the air from the bat to the time itgoes over the fence? b) By how much does the ball clear the fence? Thanks! A baseball leaves the bat with a speed of 44m/s and an angleof 30 degrees above the horizontal. A 5.0m fence is locatedat a horizontal distance of 132m from the point where the ball isstruck. Assume the ball leaves the bat 1m above the groundlevel. a) How long is the ball in the air from the bat to the time itgoes over the fence? b) By how much does the ball clear the fence? Thanks!

Explanation / Answer

Horizontal speed V = 44 cos 30 = 38.105 m / s horizontal distance X = 132 m (a). required time   t = X / V                               = 0.2886 s (b). In vertical direction : ------------------------- Initial velocity U = 44 sin 30 = 22 m / s Accleration a = -9.8 m / s ^ 2 time t = 0.2866 s from the relation y = ut + ( 1/ 2) at ^ 2                            = 6.3052 - 0.4024                            = 5.9027 m

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