An artillery shell is fired with an initial velcoity of 300 m/s at55 degrees abo

Question

An artillery shell is fired with an initial velcoity of 300 m/s at55 degrees above the horizontal. To clear the avalanche, itexplodes in the mountain side after 42 seconds. What are the x andy coordinates when shell explodes, relative to the center of theuniverse firing position?
I did 300cos(55) to get 172.0729 and then multiplied that by42 to get 7227 meters for the x. For the y, I tried 300sin(55)-9.8(42) and I got -165.85meters...which doesn't make sense.
Any ideas?
I did 300cos(55) to get 172.0729 and then multiplied that by42 to get 7227 meters for the x. For the y, I tried 300sin(55)-9.8(42) and I got -165.85meters...which doesn't make sense.
Any ideas?

Explanation / Answer

Find the x component by multiplying vo by the cosine of55
300cos(55) = 172.07 m/s
Delta x = vix(t) delta x = 172.84(42) delta x = 7227.06 m
then do 300sin(55) = 245.75 m/s This is viy
set up the equation
delta x = vo(t) + 0.5gt^2 delta x = 245.75(42) + (0.5(-9.8)(42^2)) delta x = 1677.9 m
x cood: 7227.06 m y cood: 1677.9 m

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