1) In x-y bplane, a point charge of +6C is on the x-axisat (-10cm,0), and a seco
ID: 1762106 • Letter: 1
Question
1) In x-y bplane, a point charge of +6C is on the x-axisat (-10cm,0), and a second point charge of -10C is alsolocated on the x-axis at the oint (40cm, 0). a) Determine the Electric Pontential ... VA &VB at the Ponts PA (0, 0) &PB ( 0, 30cm): b) Determine the work required (in KeV) to move an electronfrom PA to PB : 2) Determine the Energy in (Kev) needed to very slowlyseperated an electron from a proton originally separared by adistance of 50fm to a separation distance of 80 fm 1) In x-y bplane, a point charge of +6C is on the x-axisat (-10cm,0), and a second point charge of -10C is alsolocated on the x-axis at the oint (40cm, 0). a) Determine the Electric Pontential ... VA &VB at the Ponts PA (0, 0) &PB ( 0, 30cm): b) Determine the work required (in KeV) to move an electronfrom PA to PB : 2) Determine the Energy in (Kev) needed to very slowlyseperated an electron from a proton originally separared by adistance of 50fm to a separation distance of 80 fm 2) Determine the Energy in (Kev) needed to very slowlyseperated an electron from a proton originally separared by adistance of 50fm to a separation distance of 80 fmExplanation / Answer
Given q = +6 * 10 ^ -6 C q' = -10 * 10 ^ -6 CElectric potential at (0,0 ) point is V = V ' + V' where V ' = Potential at (0,0) due to q charge = K q / 10 cm = ( 8.99 * 10 ^ 9 ) ( 6 * 10 ^ -6 ) / 0.1 m = 539.4 * 10 ^ 3 Volt = 5.394* 10 ^ 5 Volt V "= Potential at (0,0) due to q 'charge = K q ' / 10 cm = ( 8.99 * 10 ^ 9 ) ( -10 * 10 ^ -6 ) / 0.1 m = 8.99 * 10 ^ 5 Volt So, V = 14.384 * 10 ^ 5 Volt = K q ' / 10 cm = ( 8.99 * 10 ^ 9 ) ( -10 * 10 ^ -6 ) / 0.1 m = 8.99 * 10 ^ 5 Volt So, V = 14.384 * 10 ^ 5 Volt
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