An amusement park ride consists of a car moving in a verticalcircle on the end o

Question

An amusement park ride consists of a car moving in a verticalcircle on the end of a rigid boom of negligible mass. The combinedweight of the car and riders is 5.1 kN,and the circle's radius is 10 m.
(a) At the top of the circle, what are the magnitudeFB and direction (up or down) of the force onthe car from the boom if the car's speed is v =4.0 m/s?

(b) At the top of the circle, what are the magnitudeFB and direction (up or down) of the force onthe car from the boom if the car's speed is v =15 m/s?

Explanation / Answer

An amusement park ride consists of a car moving in a verticalcircle on the end of a rigid boom of negligible mass. The combinedweight of the car and riders is 5.1 kN,and the circle's radius is 10 m. (a) At the top of the circle, what are the magnitudeFB and direction (up or down) of the force onthe car from the boom if the car's speed is v =4.0 m/s? force=mv*v/R=(5.1/9.8)4*4/10=0.8326N up (b) At the top of the circle, what are the magnitudeFB and direction (up or down) of the force onthe car from the boom if the car's speed is v =15 m/s? force=mv*v/R=(5.1/9.8)15*15/10=11.70N up

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