A car moving with an inital velcoity of 15m/s north has a constantacceleration o

Question

A car moving with an inital velcoity of 15m/s north has a constantacceleration of 5m/s2 south. After 2 seconds, its velocitywill be?
I cant figure out what equation should be used....Itried
V=Vo+at Vo= 15 a=5 t=2 so then V=15+(5)(2)      V=15+10    V= 25 but thats not one of my possible choices
1. 5m/s north 2. 5m/s south 3. 35 m/s north 4. 17m/s north 5. 10m/s south

I cant figure out what equation should be used....Itried
V=Vo+at Vo= 15 a=5 t=2 so then V=15+(5)(2)      V=15+10    V= 25 but thats not one of my possible choices
1. 5m/s north 2. 5m/s south 3. 35 m/s north 4. 17m/s north 5. 10m/s south

Explanation / Answer

   Since the direction of acceleration isopposite velocity, it must assume -ve value.    v0   =   15m/s    a   =   - 5m/s2    v   =   v0 +a * t   =   15 + ( - 5) *2   =   + 5 m/s    + ve sign means the direction is duenorth.    1. 5m/s north       v   =   v0 +a * t   =   15 + ( - 5) *2   =   + 5 m/s    + ve sign means the direction is duenorth.    1. 5m/s north   

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.