a = 1 m/s 2 x = 2 m The speed of a bullet as it travels down the barrel of a rif

Question

a = 1 m/s2 x = 2 m The speed of a bullet as it travels down the barrel of a rifletoward the opening is given by the expression v =(-5.10 multiplied by 107) t2 +(2.60 multiplied by 105) t, where vis in meters per second and t is in seconds. Theacceleration of the bullet just as it leaves the barrel is zero. (a) Determine the acceleration and position ofthe bullet as a function of time when the bullet is in the barrel.(Use t as necessary. Round all numerical coefficients toexactly 3 significant figures.) a = 1Click here to preview your answer.Your answer is incorrect. m/s2 x = 2Click here to preview your answer.Your answer is incorrect. m Click here for help with symbolic formatting. (b) Determine the length of time the bullet is accelerated. 3 s (c) Find the speed at which the bullet leaves the barrel. 4 m/s (d) What is the length of the barrel? 5 m Comment

Explanation / Answer

The bullet will accelerate until acceleration equals 0. Therefore set your acceleration equation to 0. 0=(-10.2 x 10^7)t+(2.6 x 10^5). solving for t will give youthe amount of time that bullet is acclerating. Once you have that time, put it back into the original velocityequation to find the speed that the bullet leaves the gunconsidering that the problem said its acceleration reaches 0 justas it leaves the barrel. Also put this time in your x equation to get the length of thebarrell I hope this helps. Good luck and please rate

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