A ball is thrown from ground to roof of height 12m fromdistance 9 m away from bu

Question

A ball is thrown from ground to roof of height 12m fromdistance 9 m away from building. Maximum height of ball'strajectory is 2 m above the top of room. What is requiredinitial velocity in vertical direction? What is time for ball to fall from maximum height torooftop? A ball is thrown from ground to roof of height 12m fromdistance 9 m away from building. Maximum height of ball'strajectory is 2 m above the top of room. What is requiredinitial velocity in vertical direction? What is time for ball to fall from maximum height torooftop?

Explanation / Answer

        Given that theheight of roof is h = 12 m         The horizontaldistance is d = 9 m         The maximum heightis H = 14 m    -------------------------------------------------       The maximum height is H =u2 sin2 /2g                                   usin = 2gH                                            = -------- m/s      This is the verticle velocity of theball        From the equation ofmotion verticle displacement is h = u sin*t -(1/2)gt2                                                                      Thenwe get t = -------sec This is the time taken to reach theheight                                                                          Thenwe get t = -------sec This is the time taken to reach theheight     Time taken to reach the maximum height is T1 =usin / g Then the time for ball to fall from maximum height torooftop is T1 - t = ------ sec

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