A technician wraps wire around a tube oflength 37 cm having a diameter of 8.3 cm

Question

A technician wraps wire around a tube oflength 37 cm having a diameter of 8.3 cm. When the windings areevenly spread over the full length of the tube, the result is asolenoid containing 590 turns of wire. a) Find theself-inductance of this solenoid.
b) If the current in this solenoid increases at the rate of 5 A/s,what is the self-induced emf in the solenoid?
a) Find theself-inductance of this solenoid.
b) If the current in this solenoid increases at the rate of 5 A/s,what is the self-induced emf in the solenoid?

Explanation / Answer

We have:
      L =   oN 2 A / l
with o = permeability of free space = 4 * 10-7 H / m         N = No.of truns =590        A = area = R 2        R = 4.15 cm = 0.0415m        l = length = 37 cm = 0.37 m => L = 6.39 * 10 -3 H          = 6.39mH b)energy stored in it when the current in its windings is 5 A is:       E = ( 1/ 2) L i2          = 79.875 mJ                                                                                                    

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