A bicyclist rides 2.37 km due east, while the resistive forcefrom the air has a

Question

A bicyclist rides 2.37 km due east, while the resistive forcefrom the air has a magnitude of 8.56 N and points due west. Therider then turns around and rides 2.37 km due west, back to herstarting point. The resistive force from the air on the return triphas a magnitude of 8.56 N and points due east. Find the work doneby the resistive force during the round trip. thank you A bicyclist rides 2.37 km due east, while the resistive forcefrom the air has a magnitude of 8.56 N and points due west. Therider then turns around and rides 2.37 km due west, back to herstarting point. The resistive force from the air on the return triphas a magnitude of 8.56 N and points due east. Find the work doneby the resistive force during the round trip. thank you

Explanation / Answer

But because the direction of the resistive changes when the cyclistchanges directions this cannot be assumed. so shouldn't the workdone be: The definition of work is Force times distance: W=F*D Distance is equal to xf-xi or the final pointminus the inital point. so for part 1 of the trip D=(2.37km)-(0km)=2.37km The force is against (opposite) the direction of travel as well asmoving right to left. Therefore it is a negative quantity. F=(-8.56N) so the work done on the first leg of the trip: W=(-8.56*2.37) the work done on the second part of the trip is then: W=(F*D) W=(8.56)*(0-2.37km) W=8.56*-2.37 so the second leg of the trip produces an equal amount of worktherefore: W=-2(8.56*2.37) N(km) The normal unit of work is joules and is defined as Newton Metersso do a simple unit conversion: W(joules)=-2(8.56N*2.37km)*(1000m/1km)

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