A ray of light strikes the midpoint of one face of anequiangular (60° -60° -60°)

Question

A ray of light strikes the midpoint of one face of anequiangular (60° -60° -60°) glass prism (n = 1.5)at an angle of incidence of 28°. (a) Trace the path of the light ray through theglass, and find the angles of incidence and refraction at eachsurface.
1st surface: incidence = 1° refraction = 2° 2nd surface: incidence = 3° refraction = 4°
(b) If a small fraction of light is also reflected at each surface,find the angles of reflection at the surfaces. reflection = 5° (1st surface) reflection = 6° (2nd surface) (a) Trace the path of the light ray through theglass, and find the angles of incidence and refraction at eachsurface.
1st surface: incidence = 1° refraction = 2° 2nd surface: incidence = 3° refraction = 4°
(b) If a small fraction of light is also reflected at each surface,find the angles of reflection at the surfaces. reflection = 5° (1st surface) reflection = 6° (2nd surface) incidence = 1° refraction = 2°

Explanation / Answer

A ray of light strikes the midpoint of one face of an equiangular(60° -60° -60°) glass prism (n = 1.5) at anangle of incidence of 28°. (a)Trace the path of the light ray through the glass, and find theangles of incidence and refraction at each surface. 1st surface: angle of incidence=28degree n=1.5 from snell law n=sini/sinr sinr=sini/n=sin28/1.5=0.3129 so r=angle ofrefraction=18.23degree incidence = 1° refraction = 2° 2nd surface: at the second surface r2=A-r1=60-18.23=41.77degree hence from snell law n=sini/sinr sini=sinr*n=sin41.77*1.5=0.9992 so i=angle of incidence at the second surface=87.72degree incidence = 3° refraction = 4° (b) If a small fraction of light is also reflected at each surface,find the angles of reflection at the surfaces. angle of reflection at the first surface=28degree angle of reflection at the second surface=41.77degree reflection = 5° (1st surface) reflection = 6° (2nd surface)

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