A ray of light comes to the interface that is part of a sphere of radius=15.0cm.

Question

A ray of light comes to the interface that is part of a sphere of radius=15.0cm. The media are air on the convex, incident side and glass of index of refraction n=1.50 on the other side. What is the focal length if the interface is treated as a lens? A ray of light comes to the interface that is part of a sphere of radius=15.0cm. The media are air on the convex, incident side and glass of index of refraction n=1.50 on the other side. What is the focal length if the interface is treated as a lens?

Explanation / Answer

We know that,

Using the lens makers formula yields:  1/f = (n-1)( 1/R1 + 1/R2)

R1 = 15 cm and R2 = 15 cm, if biconvex lens

or, 1/f = (1.5-1)((1/15)+(1/15)) = 1/15

or, f = 15 cm

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