What is the angle of incidence, Beta, that this ray makes with thenormal to the

Question

What is the angle of incidence, Beta, that this ray makes with thenormal to the floor of the tank ? Take alpha= 31.6o.Answer in units of degrees.
A solid glass ramp is sitting on the floor of a tank of water. Theindex of refraction of the glass is 1.73, while that of the wateris 1.37. A ray of light moving vertically as shown in the figure isrefracted at the water-glass interface and reaches thefloor. What is the angle of incidence, Beta, that this ray makes with thenormal to the floor of the tank ? Take alpha= 31.6 degree.Answer in units of degrees.

Explanation / Answer

Applying Snell's law to the water-glass interface wehave n1 * sin1 = n2 *sin2 --------(1) n1 = 1.37 1 = 90o n2 = 1.73 from equation (1) we get sin2 = (n1 *sin1/n2) or 2 = sin-1(n1 *sin1/n2) or 2 = sin-1(1.37 *sin(90o)/1.73) = 52.3o from the triangle formed in the figure we have + 3 + 4 =180o 3 = 2 + 90o and4 = + 90o or + 2 + 90o + +90o = 180o or = - - 2 = 31.6o or = -31.6o - 52.3o =-83.9o the negative value of angle indicates that isgiven by = 90o - 83.9o =6.1o the negative value of angle indicates that isgiven by = 90o - 83.9o =6.1o

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.