2. If you place an object very far from themirror, what is the location of the i
ID: 1757325 • Letter: 2
Question
2. If you place an object very far from themirror, what is the location of the image?Answer: : 37.3cm
3. What is the magnification of theimage?Answer: :0
5. What is the magnification of theimage?Answer: :-1.7
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NEED ONLY HELP WITH QUESTIONS 6and 7 thanks
6. If a diverging lens of focal length -67.0cm is then placed 27.0 cm from the first lens on the opposite sideof the lens from the object, what is the location of the newimage?
Answer: ?????
Hint: If you know themagnification of the first lens and the magnification of the secondlens, you are just about there.
7. What is the magnification due to thetwo-lens system?
Answer: ????
NEED ONLY HELP WITH QUESTIONS 6and 7 thanks
Explanation / Answer
From the Problem (5) Image distance (v) = 81.0 cm This image distance becomes object distance for the secondlens. Objectdistance of the second lens is : u1 = 27.0 cm - 81.0 cm = -54 cm Focal lenght (f1) = -67.0 cm We have : 1 / f1 = 1 / u1 + 1 / v1 or 1 / v1 = 1 / f1 - 1 / u1 = - 1 / 67.0 + 1 / 54.0 New Image distance of the two lens system is: v1 = 227.8 cm Total magnification is : M = M1 * M2 = - 1.7 * ( - v1 / u1) = 1.7 * (227.8 / 54.0) = 7.17 Hope this helps u!Related Questions
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