2. If you place an object very far from themirror, what is the location of the i

Question

2. If you place an object very far from themirror, what is the location of the image?Answer: : 37.3cm
3. What is the magnification of theimage?Answer: :0

5. What is the magnification of theimage?Answer: :-1.7

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NEED ONLY HELP WITH QUESTIONS 6and 7 thanks

6. If a diverging lens of focal length -67.0cm is then placed 27.0 cm from the first lens on the opposite sideof the lens from the object, what is the location of the newimage?

Answer:   ?????

Hint: If you know themagnification of the first lens and the magnification of the secondlens, you are just about there.
7. What is the magnification due to thetwo-lens system?

Answer: ????

NEED ONLY HELP WITH QUESTIONS 6and 7 thanks

Explanation / Answer

Given : Radius of curvature ( R ) = 74.6cm. 1 ) focal length ( f ) = R / 2                          = 74.6 /2 = 37.3 cm 2 ) for a very far objects focal length = imagedistance                                                           = 37. 3 cm    Magnification for lens = -v/u

where, v= image distance from lens
and u= object distance from lens..

Now, the image of the first lens will act as object for diverginglens,use the lens formula and take out the new image.

new magnification = -distance of new image/distance of oldobject. I hope it helps you Magnification for lens = -v/u

where, v= image distance from lens
and u= object distance from lens..

Now, the image of the first lens will act as object for diverginglens,use the lens formula and take out the new image.

new magnification = -distance of new image/distance of oldobject. I hope it helps you

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